When is horizontal acceleration zero

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To increase vehicle safety, should the time of the impact be increased or decreased? What is the Work Done? How can the force and distance travelled be used to find the work done? Use "work done" to define the Joule. Define power in terms of work done. How can the power be found given an object's force and velocity? How can the power be found given the work done over a period of time t? What is the principle of conservation of energy? How can the efficiency be calculated? What is the kinetic energy equation?

What energy transfer occurs when eating food? Since, the velocity is constant in horizontal direction so the rate of change of velocity i. Horizontal motion is defined as a projectile motion in a horizontal plane depending upon the force acting on it.

For a short distance, the vertical and horizontal components of a projectile are perpendicular and independent of each other. Motion in a plane is also called a motion in two dimensions. The horizontal velocity remains constant, because there is no acceleration in that direction. At the highest point, only the horizontal component of velocity is present and the vertical component is zero.

The initial horizontal velocity can also be determined by measuring the diameter d of the ball and dividing by the time t that it takes for the ball to move across the photogate. However, the horizontal component of its velocity is not zero. The instantaneous speed of any projectile at its maximum height is zero. Because gravity provides the same acceleration to the ball on the way up slowing it down as on the way down speeding it up , the time to reach maximum altitude is the same as the time to return to its launch position.

At maximum height, the ball is momentarily at rest as it changes its direction of motion before accelerating towards the surface of earth. Hence at maximum height the magnitude of velocity is zero and acceleration is same as the acceleration due to gravity ie. By taking the vector to be analyzed as the hypotenuse, the horizontal and vertical components can be found by completing a right triangle. The bottom edge of the triangle is the horizontal component and the side opposite the angle is the vertical component.

Here the acceleration is constant, being equal to g. The vertical motion of the projectile is subjected to uniform accleration in the downward direction and this acceleration is equal to ''g'' acceleration due to gravity. Air resistance and other forces are negligible. There is no horizontal acceleration on the projectile i.

Please approve my answer if you liked it by clicking on "Yes" given below! Please choose valid name. Please Enter the valid Email. Select Grade 6th 7th 8th 9th 10th 11th 12th 12th Pass Please choose the valid grade. We receieved your request Stay Tuned as we are going to contact you within 1 Hour Close. Thank you for registering. The important concept depicted in the above vector diagram is that the horizontal velocity remains constant during the course of the trajectory and the vertical velocity changes by 9.

These same two concepts could be depicted by a table illustrating how the x- and y-component of the velocity vary with time. The numerical information in both the diagram and the table above illustrate identical points - a projectile has a vertical acceleration of 9.

This is to say that the vertical velocity changes by 9. This is indeed consistent with the fact that there is a vertical force acting upon a projectile but no horizontal force. A vertical force causes a vertical acceleration - in this case, an acceleration of 9. But what if the projectile is launched upward at an angle to the horizontal?

How would the horizontal and vertical velocity values change with time? How would the numerical values differ from the previously shown diagram for a horizontally launched projectile? The diagram below reveals the answers to these questions.

The diagram depicts an object launched upward with a velocity of